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Question: What is the refractive index of the material of Plano-convex lens, if the radius of curvature of the...

What is the refractive index of the material of Plano-convex lens, if the radius of curvature of the convex is 10cm10cm and focal length of the lens is 30cm?30cm?
(A) 13\dfrac{1}{3}
(B) 11
(C) 43\dfrac{4}{3}
(D) 23\dfrac{2}{3}

Explanation

Solution

Hint In the question they have provided the radius of curvature of the convex and the focal length of the lens. The given lens is a Plano convex lens. We have to find the refractive index of the material of the Plano-convex lens.
Hint:

Complete step by step answer
A lens is an optical device that focuses or disperses a light beam by refraction. Lens are of two types a simple lens and a compound lens. A simple lens has a single piece of transparent material that can be a glass or plastic, while a compound lens consists of several simple lenses, arranged along a common axis. A lens usually focuses light by refraction to form an image.
Plano convex lens is a lens that has one plane side and one convex side.
The relation between the radius of curvature of the lens and the focal length the lens is given by:
1f=(n1)(1R11R2)\dfrac{1}{f} = (n - 1)\left( {\dfrac{1}{{{R_1}}} - \dfrac{1}{{{R_2}}}} \right)
f is the focal length of the lens
n is the refractive index of the lens
R1{R_1} is the radius of curvature of the convex surface
R2{R_2} is the radius of curvature of the plane-surface
Given,
Focal length of the lens is 30cm30cm
The radius of curvature of the convex is 10cm10cm
The radius of the curvature of the plane-surface is infinite for a of Plano-convex lens
So, the radius of the curvature of the plane-surface is \infty
We have seen that the relation between the radius of curvature of the lens and the focal length the lens is given by:
1f=(n1)(1R11R2)\Rightarrow \dfrac{1}{f} = (n - 1)\left( {\dfrac{1}{{{R_1}}} - \dfrac{1}{{{R_2}}}} \right)
Substitute the given values
130=(n1)(1101)\Rightarrow \dfrac{1}{{30}} = (n - 1)\left( {\dfrac{1}{{10}} - \dfrac{1}{\infty }} \right)
130=(n1)(1100)\Rightarrow \dfrac{1}{{30}} = (n - 1)\left( {\dfrac{1}{{10}} - 0} \right)
130=(n1)110\Rightarrow \dfrac{1}{{30}} = (n - 1)\dfrac{1}{{10}}
10=30(n1)\Rightarrow 10 = 30(n - 1)
10=30n30\Rightarrow 10 = 30n - 30
10+30=30n\Rightarrow 10 + 30 = 30n
40=30n\Rightarrow 40 = 30n
n=43\therefore n = \dfrac{4}{3}
The refractive index of the Plano convex lens is 43\dfrac{4}{3}

Hence the correct answer is option (C) 43\dfrac{4}{3}

Note We have seen that the relation between the radius of curvature of the lens and the focal length the lens is:
1f=(n1)(1R11R2)\Rightarrow \dfrac{1}{f} = (n - 1)\left( {\dfrac{1}{{{R_1}}} - \dfrac{1}{{{R_2}}}} \right)
This relation is known as the lens maker’s formula because it helps to find the curvature needed to make a lens of desired focal length. This formula is applicable to find curvature of concave lenses also.