Question
Question: What is the reading of ammeter in adjoining circuit diagram?  in this given circuit. As we all know that for KVL we should have to define some current for each of the segment of the given circuit
So, the diagram can be redrawn as
From the above diagram we can say that “I” is the amount of current flowing through the ammeter and
I = I1+I2 …...……… (a)
Applying K.V.L. in Loop 2 we get,
2−2I−2I2=0
or
2I+2I2=2 ………… (1)
I=22−2I2 ………………. (2)
Now applying KVL in Loop 1 we get,
2I1+2I=2 ………….. (3)
Putting the value of “I” from equation (2) we get
2(I1−I2)=0
I1=I2 ……… (4)
Now putting the value of I1 from equation (4) in equation we get
I=2I2
Putting this value in equation (1) we get
2(2I2)+2I2=2
I2=31
Now since I1=I2
Therefore, I1=31
Putting both the values in equation (a) we get,
I = I1+I2
I=32A
Therefore, the current through the ammeter is 32A.
So, we can conclude that the ammeter will show a reading of 32A
Note: In the above question there were three variables so we need three equations to solve this, but there are only two loops so we can make only two equations using KVL. So, in this case we need to find the third equation by solving both the equations and finding the relation in between two equations