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Question

Question: What is the range of wavelength of the spectrum of white light in \( \mathop A\limits^\circ \) ? (...

What is the range of wavelength of the spectrum of white light in A\mathop A\limits^\circ ?
(A) 4000A04000{A^0} to 5000A5000 \mathop A\limits^\circ
(B) 5000A05000{A^0} to 6000A6000 \mathop A\limits^\circ
(C) 6000A06000{A^0} to 8000A8000 \mathop A\limits^\circ
(D) All of the above

Explanation

Solution

Hint : To solve this question, we need to look at the components of the colors that the white light consists of. Then with the help of the EM spectrum we can easily get the required range of the wavelength, which falls in the visible region.

Complete step by step answer
White light is that part of the electromagnetic radiation, which is visible to the human eyes. So the region of the EM spectrum, which consists of the white light, is termed as the visible region of the EM spectrum. When the white light is passed through a prism, then after getting refracted through the prism, it gets split into its seven components. This phenomenon is termed as dispersion. The seven components of the white lights thus obtained are represented by VIBGYOR. Here V stands for violet, I stands for indigo, B stands for blue, G stands for green, Y stands for yellow, O stands for orange, and R stands for red. These get split due to difference in their wavelengths. Their wavelength range from the blue colored light has the minimum wavelength of about 400nm400nm , to the red colored light, which has the maximum wavelength of about 750nm750nm . So the range of white light is from 400nm400nm to 750nm750nm . Now, we now that
1nm=109m1nm = {10^{ - 9}}m …………………...(1)
1A=1010m1 \mathop A\limits^\circ = {10^{ - 10}}m …………………...(2)
Dividing (1) by (2) we get
1nm1A=109m1010m\dfrac{{1nm}}{{1 \mathop A\limits^\circ }} = \dfrac{{{{10}^{ - 9}}m}}{{{{10}^{ - 10}}m}}
1nm=10A\Rightarrow 1nm = 10 \mathop A\limits^\circ
Thus, the range of white can be written as from 4000A4000 \mathop A\limits^\circ to 7500A7500 \mathop A\limits^\circ .
So we see that all of the three ranges given in the option A, B, and C are correct.
Hence, the correct answer is option D.

Note
We should not get confused by the range given in the option C, which has a maximum wavelength of 8000A8000 \mathop A\limits^\circ , different from the maximum wavelength of red light of 7500A7500 \mathop A\limits^\circ . As both of the options A and B are correctly matching, so we have to consider all of the options to be correct, by assuming this difference to be negligible.