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Question

Question: What is the quadratic formula?...

What is the quadratic formula?

Explanation

Solution

A polynomial of the form ax2+bx+c,a0a{x^2} + bx + c,a \ne 0 and when we equate this polynomial to zero i.e.ax2+bx+c=0,a0a{x^2} + bx + c = 0,a \ne 0, then the equation/formula we get is known as quadratic equation or quadratic formula.

Complete step-by-step solution:
Let us take an example of blackboard of our school which usually has rectangular shape,

Now we have two information regarding the blackboard, first is the area of blackboard is 10m210{m^2} and the length is one meter more than twice its breadth
As we know that,
Area of rectangle =length×breadth = length \times breadth
So we have,
Area of rectangle =(2x+1)×(x) = (2x + 1) \times (x)
(2x+1)×(x)=10(2x + 1) \times (x) = 10 (Given)
After multiplication we get,
2x2+x=102{x^2} + x = 10
Therefore, 2x2+x10=02{x^2} + x - 10 = 0
So, the breadth of the blackboard should satisfy the equation 2x2+x10=02{x^2} + x - 10 = 0 which is a quadratic equation.
A quadratic equation is an equation of the form ax2+bx+c=0a{x^2} + bx + c = 0, where a, b, c are real numbers and a0a \ne 0. For example, 2x2+x10=02{x^2} + x - 10 = 0 is a quadratic equation. We can also say that, any equation of the form p(x)=0p(x) = 0, where p(x)p(x) is a polynomial of degree 22 , is a quadratic equation. But by writing the terms of p(x)p(x) in descending order of their degrees, we get the standard form of the equation. ax2+bx+c=0a{x^2} + bx + c = 0 , a0a \ne 0 is called the standard form of a quadratic equation.
The Solution of quadratic equation and relation between roots and coefficient:

The solutions of the quadratic equation, ax2+bx+c=0a{x^2} + bx + c = 0 is given by x=b±b24ac2ax = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}
The expression b24ac=D{b^2} - 4ac = D is called the discriminant of the quadratic equation.
If α & β\alpha {\text{ }}\& {\text{ }}\beta are the roots of the quadratic equation ax2+bx+c=0a{x^2} + bx + c = 0 then;

  1. α+β=ba\alpha + \beta = - \dfrac{b}{a}
  2. αβ=ca\alpha \beta = \dfrac{c}{a}
  3. αβ=Da\left| {\alpha - \beta } \right| = \dfrac{{\sqrt D }}{{\left| a \right|}}

Quadratic equation whose roots are α & β\alpha {\text{ }}\& {\text{ }}\beta is (xα)(xβ)=0(x - \alpha )(x - \beta ) = 0 i.e.
x2(α+β)x+αβ=0{x^2} - (\alpha + \beta )x + \alpha \beta = 0 i.e. x2{x^2} - (sum of roots) x$$$$ + product of roots =0 = 0
Nature of Roots: Consider the quadratic equation ax2+bx+c=0a{x^2} + bx + c = 0 where a,b,cR&a0a,b,c \in R\& a \ne 0 then;
D>0D > 0 \Leftrightarrow Roots are real & distinct (unequal).
D=0D = 0 \Leftrightarrow Roots are real & coincident (equal).
D<0D < 0 \Leftrightarrow Roots are imaginary.

Note: To solve a quadratic equation by factoring,

Rearrange the equation and take all terms on one side of the equal sign and zero on the other side.
Factorize the equation.
Take each factor equal to zero and solve each equation.
Check the calculated answer by putting it in the original equation.