Question
Question: What is the purity of concentrated \[{H_2}S{O_4}\] solution (\[d = 1.8g/mol\] ) if \[5mL\] of these ...
What is the purity of concentrated H2SO4 solution (d=1.8g/mol ) if 5mL of these solution is neutralized by 84.5mL of 2N$$$$NaOHsolution.
A. 93%
B. 94.6%
C. 92.12%
D. 91.5%
Solution
The purity of a solution is the percentage purity of a substance which is evaluated by ratio of the mass of the pure substance and the total mass of the sample considered multiplied by 100.
Complete step by step answer:
The given reaction is a neutralization reaction between an acid and a base. The acid used is sulfuric acid and the base used is sodium hydroxide. The corresponding balanced reaction is as follows:
H2SO4+2NaOH→Na2SO4+H2O
The volume of NaOH solution used in the neutralization process is 84.5mL. The Normality of the solution used is 2N. The moles of NaOH used is determined as
=10002×84.5=0.169moles
Following the above equation it is clear that two equivalents of NaOH is used for consumption of 1 equivalent of H2SO4. Thus for two moles of NaOH solution, one mole of H2SO4 is used for neutralization.
Hence for 0.169moles of NaOH, moles of H2SO4 used are = 20.169=0.0845moles.
A mole of substance is the ratio of the mass of the substance and the molar mass of the substance. Hence mole=molar mass of substancemass of substance
Molar mass of H2SO4 = 2 × atomic mass of H + atomic mass of S + 4 × atomic mass of O
=2×1+32+4×16=98g/mol
The mass of H2SO4 in 0.0845moles = moles of H2SO4 × molar mass of H2SO4.
=0.0845×98=8.281g
The total mass of H2SO4 which is used in the reaction is = density × volume =1.8×5=9g.
Hence the purity of the concentrated H2SO4 solution
=98.281×100=92.01%
Thus option C is the correct answer.
Note: The purity or percentage of purity of a substance is determined using Quantitative chemistry calculations. The number of moles of the substance is the key to determine the purity of the substance.