Question

What is the product when ${C_6}{H_5}C{H_2}N{H_2}$ reacts with $HN{O_2}$?

Answer 1

We need to identify the reactants and understand the reaction that takes place. The given reactants are Benzylamine and nitrous acid. The organic chemical compound benzylamine has the condensed structural formula ${C_6}{H_5}C{H_2}N{H_2}$. It is made up of a benzyl functional group, ${C_6}{H_5}C{H_2}$, and an amine functional group, $N{H_2}$. Nitrous acid is an oxoacid of nitrogen. It is a nitrite conjugate acid.

Complete answer:
When Benzylamine reacts with nitrous acid, the first product formed is a diazonium salt. Diazonium compounds, also known as diazonium salts, are a class of organic compounds that share the functional group $RN + {\text{ }}2X$, where $R$ can be any chemical group, such as an alkyl or an aryl, and $X$can be an inorganic or organic anion, such as a halogen. This diazonium salt is transformed into an alcohol. The alcohol produced is Benzyl alcohol. Two by-products are also formed which are nitrogen and water. The reaction is given as follows:
${C_6}{H_5}C{H_2}N{H_2}$+ $HN{O_2}$→ ${C_6}{H_5}C{H_2}OH$+ ${N_2}$+${H_2}O$
Hence, the product when ${C_6}{H_5}C{H_2}N{H_2}$ reacts with $HN{O_2}$ is ${C_6}{H_5}C{H_2}OH$ which is benzyl alcohol along with ${N_2}$ and ${H_2}O$ as by-products.

Note:
Note that the IUPAC name of benzyl alcohol is phenyl methanol. Diazonium salts are made using nitrous acid. Such salts are frequently employed in organic synthesis, for example, in the Sandmeyer reaction and in the production of azo dyes, which are vividly coloured compounds that serve as the foundation of a qualitative aniline test. Toxic and possibly explosive sodium azide is destroyed with nitrous acid. Nitrous acid is often produced in situ by the action of mineral acid on sodium nitrite. It is mostly blue in colour.