Question

What is the product of the following reactions?

(A)

(B)

(C)

(D)

Answer 1

Hint : We know that the hydroboration oxidation is an anti-markovnikov addition of water across alkene. Also, it is a two-step organic reaction. Hydroboration oxidation reaction is another important chemical reaction of organic chemistry which converts alkene into an alcohol. This reaction gives a more stereo specific and regiochemical alternative to other hydration reactions such as acid-catalyzed addition and oxymercuration reduction reactions.

Complete Step By Step Answer:
Hydroboration oxidation reaction is a two-step reaction in which alkene reacts with $B{{H}_{3}},$ THF (tetrahydrofuran) and hydrogen peroxide in a basic medium to give alcohol. It is also known as $HBO$ reaction. Hydroboration oxidation of symmetrical alkene and unsymmetrical alkene works differently. As the reaction proceeds with unsymmetrical alkene follows Anti-Markovnikov rule. Although as a product we always get alcohol from both alkenes.
It is known to you that hydroboration oxidation is a two-step organic reaction. It is an organic reaction that converts an alkene into an alcohol by the net addition of water across the double bond. THF (Tetrahydrofuran) is used as a solvent. The hydrogen $\left( H \right)$ and hydroxyl group $\left( OH \right)$ are added in a syn (addition of addendum on the same side of the alkene or alkyne) addition leading to cis stereochemistry. Hydroboration-oxidation is an anti-Markovnikov’s addition of water across an alkene. The $-OH$ group is added to the less substituted position and the -H is in the more substituted position. If there is more than one chiral center in the product, then the product will produce a pair of enantiomers that results from syn addition.
Here, we can see that first, is added to the carbon-carbon double bond in a way that $H-$ atoms get bonded to a carbon that has less number of hydrogen atoms(means in an anti-markovnikov manner). Then, in presence of hydrogen peroxide-an oxidizing agent, the organo-borane compound decomposes and gives an alcohol as shown in the reaction. One molecule can oxidise three molecules of alkene because one $B-H$ bond is responsible for the oxidation of one molecule of alkene.

Therefore, the correct answer is option B.

Note :
Remember that it's necessary to understand the chemistry of $B{{H}_{3}}$ before understanding the mechanism of hydroboration oxidation reaction. As boron has one p-orbital empty so $B{{H}_{3}}$ acts as Lewis acid. It exists as a dimer of $B{{H}_{3}},$ it means it exists in the form of ${{B}_{2}}{{H}_{6}}2B{{H}_{3}}\to {{B}_{2}}{{H}_{6}}$ .