Question

What is the product formed when Sulphur dioxide is dissolved in water?
A. ${H_2}S{O_3}\\\$
B. ${H_2}S{O_4}\\\$
C. ${H_2}{S_2}{O_7}\\\$
D. None of these

Answer 1

As we can see the question pinpoint that the formation of the product is to be known if acid dissolves in water. The acid mentioned here in the options is diprotic acid which has two hydrogen atoms which can be replaced if needed. The acid formed will be different, if the number of oxygen atoms attached to the sulphur atom varies.

Complete step by step solution
The properties and uses of the sulfur dioxide are as follows, it has a chemical formula $S{O_2}$, It does not have a color like iodine gas have, it has suffocating odor. It is readily soluble in cold water same as salt it is a chemical molecule sparingly soluble in hot water same as calcium chloride, and it is soluble in alcohol, acetic acid, and sulfuric acid to produce solution, hence it is use in industry as solvent, in hospitals as disinfectants, coolants, preservative, etc. It is corrosive to organic materials and dissolves in water to form sulfurous acid, ${H_2}S{O_3}$. The reaction is as follows:
$S{O_2} + {H_2}O \to {H_2}S{O_3}$

Hence, the correct answer is (A). Other options given in the question are made by further oxidation of sulfurous acid.

Note:
The oxidation of sulphurous acid gives sulphuric acid which causes air-pollution and acid rain. Majority of industries produce such acids as by-products which causes air pollution. ${H_2}{S_2}{O_7}$is used to produce dyes, to produce nylon, in the sulphonation process. ${H_2}S{O_4}$ is used as solvent in the industry. It is used to produce ester.it is used to produce paints, fertilizers, etc. ${H_2}S{O_3}$ is used to produce ${H_2}S{O_4}$. It is used as a strong reducing agent and has bleaching properties.