Question

What is the probability that an ordinary year has $53$ Tuesdays?

• A. $\frac{1}{8}$
• B. $\frac{1}{7}$
• C. $\frac{1}{9}$
• D. $\frac{2}{9}$

Answer 1

Answer: (B)

$\frac{1}{7}$

Answer 2

An ordinary year has $365$ days, i.e., $52$ weeks and $1$ day. Now, $52$ weeks have $52$ Tuesdays and the remaining one day can be any of the $7$ days. $\therefore$ Required probability = probability of this day being a Tuesday =$\frac{1}{7}$.