Question
Question: What is the potential energy of this configuration of three charges? 
Solution
In order to solve this question, we are going to firstly analyze the configuration of the three charges and we will find the potential energy of the charges taking two at a time, one by one, then, the total potential energy of the configuration is found by adding the three potential energies as calculated.
Formula used: The potential energy of the two charges is given as:
U3=−4πε01rq1q2
Where, ris the distance between the two charges q1andq2.
Complete step-by-step solution:
It is given that the three charges are given in the configuration as above, if we find the potential energy taking two charges at a same time then, adding them can give the total potential energy of the configuration.
Let us first take the two charges, qand2q, which are at a distance of a
Then, the potential energy is equal to:
U1=4πε01a2q2
Now, taking the two charges 2qand−q, which are at a distance ofa
Then, the potential energy is equal to:
U2=−4πε01a2q2
Taking the other two charges, qand−q, the distance between them is found by Pythagoras theorem,
s=a2+a2=2a
Thus, potential energy is given by
U3=−4πε01aq2
Therefore, the total potential energy is equal to the sum of the three as given by:
U=U1+U2+U3=4πε01(a2q2−a2q2−2aq2)
Solving this equation, we get,
U=42πε0a−q2
Note: It is important to note that the potential energy is the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors. It is taken for two charges at a time when more than the two charges are given, then the potential energies are found taking two charges each one by one.
