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Question: What is the potential energy of the equal positive point charges of \(1\mu C\) each held 1 m apart i...

What is the potential energy of the equal positive point charges of 1μC1\mu C each held 1 m apart in air

A

9×10−3J9 \times 10^{- 3}J

B

9×10−3eV9 \times 10^{- 3}eV

C

2eV/m2eV/m

D

Zero

Answer

9×10−3J9 \times 10^{- 3}J

Explanation

Solution

By using U=9×109Q1Q2rU = 9 \times 10^{9}\frac{Q_{1}Q_{2}}{r}

⇒ U=9×109×10−6×10−61=9×10−3JU = 9 \times 10^{9} \times \frac{10^{- 6} \times 10^{- 6}}{1} = 9 \times 10^{- 3}J