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Question: What is the \(pOH\) of an aqueous solution with hydrogen ion concentration equal to \(3 \times {1...

What is the pOHpOH of an aqueous solution with hydrogen ion concentration equal to
3×105mol/l3 \times {10^{ - 5}}mol/l
A. 9.479.47
B. 4.524.52
C. 12.6912.69
D. 11.6911.69

Explanation

Solution

We all know that pHpH is a scale used to specify the acidity or basicity of an aqueous solution. In order to calculate we need to use this equation pH+pOHpH + pOH = 1414.

Complete answer:
The pHpH and pOHpOH of a solution come from the hydrogen ions and the hydroxide ions that form at equilibrium. They serve as an indicator of the strength of the solution whether it be acidic or basic. pHpH is a measure of hydronium ion concentration.
As in the question the concentration of hydrogen ions is given as 3×105mol/l3 \times {10^{ - 5}}mol/l
[H+]=[{H^ + }] = 3×105mol/l3 \times {10^{ - 5}}mol/l
We know the pHpH can be found out using the formula pH=log[H+]pH = - \log [{H^ + }] where log\log is to the base 1010.
Therefore
pHpH =log(3×105) = - \log (3 \times {10^{ - 5}})
Using the property of log that is log(ab)=loga+logb\log (ab) = \log a + \log b we can write
pH=(log3+log105)pH = - (\log 3 + \log {10^{ - 5}})
Now again we can use the property of log as logab=bloga\log {a^b} = b\log a
So using this property we can expand this equation as follow
pH=(log35log10)pH = - (\log 3 - 5\log 10)
Now we know that log10=1\log 10 = 1, and value of log3=0.4771\log 3 = 0.4771 using this we can write
pH=(log35) pH=5log3 pH=50.4771 pH=4.5229  pH = - (\log 3 - 5) \\\ pH = 5 - \log 3 \\\ pH = 5 - 0.4771 \\\ pH = 4.5229 \\\
From the value of pHpHwe can easily calculate the pOHpOHusing the equation pH+pOH=14pH + pOH = 14.
As we know that pOHpOH == 1414 - pHpH
pOHpOH
=144.5229 =9.47  = 14 - 4.5229 \\\ = 9.47 \\\

So the answer is A.

Note:
pHpH is a scale used to specify the acidity or basicity of an aqueous solution. Acidic solutions have lower pHpH values and basic solutions have higher pHpH values. The range of pHpH is 1414. If the value of pHpH is 77then it is neutral. Learn thoroughly about the exception cases.