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Question

Chemistry Question on Equilibrium

What is the pHpH value of MH2SO4M H _{2} SO _{4} ?

A

0

B

-0.213

C

-2

D

-0.301

Answer

-0.301

Explanation

Solution

The correct answer is Option is D) -0.301

MH2SO4=2NH2SO4M H _{2} SO _{4} =2 N H _{2} SO _{4}
[H+]=Nα\left[ H ^{+}\right] =N \cdot \alpha
=2×1=2=2 \times 1=2
pH=log[H+]pH =-\log \left[ H ^{+}\right]
=log2=-\log 2
=0.3010=-0.3010

Read more from chapter:**Equilibrium **