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Question: What is the pH of a solution obtained by mixing 10 mL of \(2NO_{(g)} + Cl_{2(g)}\)M HCl and 40 mL of...

What is the pH of a solution obtained by mixing 10 mL of 2NO(g)+Cl2(g)2NO_{(g)} + Cl_{2(g)}M HCl and 40 mL of 2NOCl(g)2NOCl_{(g)}M KPQPK_{P}Q_{P}?

A

QP>KPQ_{P} > K_{P}

B

QP<KPQ_{P} < K_{P}

C

QP=0Q_{P} = 0

D

KcK_{c}

Answer

KcK_{c}

Explanation

Solution

: Millimoles of H+H^{+} from HCl,=0.1×10=1= 0.1 \times 10 = 1

Millimoles of H+H^{+} from H2SO4=0.2×40×2=16H_{2}SO_{4} = 0.2 \times 40 \times 2 = 16

Conc. of H+=MillimolesVolume=16+140+10=1750=0.34H^{+} = \frac{Mil\lim oles}{Volume} = \frac{16 + 1}{40 + 10} = \frac{17}{50} = 0.34

pH=log[H+]=(0.34)=0.468pH = - \log\lbrack H^{+}\rbrack = - (0.34) = 0.468