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Question: What is the pH of \( 0.45M \) \( {H_2}S{O_4} \) ?...

What is the pH of 0.45M0.45M H2SO4{H_2}S{O_4} ?

Explanation

Solution

pH of a solution is the negative logarithm of concentration of H+  {H^ + }\; ions. pH helps to identify whether a solution is acidic, basic or neutral. In the question molarity of sulphuric acid is given, from this molarity find out the H+  {H^ + }\; ion concentration and then using the formula pH can be found out. The formula for pH is: pH=log[H+]pH = - log[{H^ + }]

Complete Step By Step Answer:
pH is defined as the negative logarithm of H+  {H^ + }\; ion concentration. It is a measure of how acidic/basic water or any solution is.
The measurement was originally used by the Danish biochemist S.P.L. Sorensen to represent the hydrogen ion concentration, expressed in equivalents per litre, of an aqueous solution. Its formula is given as:
pH=log[H+]pH = - log[{H^ + }]
In the question given above we have to determine the pH of 0.45M0.45M of strong acid H2SO4{H_2}S{O_4} . It is known that the sulphuric acid H2SO4{H_2}S{O_4} is a strong acid as it dissociates completely in water. And this ionization is hardly affected by the presence/absence of other solutes present in the same solution. Therefore dissociation occurs like,
H2SO42H++SO4(2){H_2}S{O_4} \to 2{H^ + } + SO_4^{(2 - )}
The concentration of H2SO4{H_2}S{O_4} is given as 0.45M0.45M . So it can be written as:
[H2SO4]=0.45M[{H_2}S{O_4}] = 0.45M
Now we know that pH is also the concentration of hydrogen ions in the solution. and also you should know that 11 mole of H2SO4{H_2}S{O_4} gives 22 mole of H+  {H^ + }\; ions therefore its concentration will be double the concentration of H2SO4{H_2}S{O_4} and thus:
[H+]=2 [H2SO4][{H^ + }] = 2{\text{ }}[{H_2}S{O_4}]
[H+]=2×0.45\Rightarrow [{H^ + }] = 2 \times 0.45
[H+]=0.9M\Rightarrow [{H^ + }] = 0.9M
Now that we have found out the value of H+  {H^ + }\; we can substitute this value in the formula to find out the pH of the sulphuric acid.
Thus, pH=log[H+]pH = - log[{H^ + }]
pH=log[0.9]\Rightarrow pH = - log[0.9]
pH=(0.04575)\Rightarrow pH = - \left( { - 0.04575} \right)
pH=+0.04575\Rightarrow pH = + 0.04575
Therefore the value of pH is +0.04575+ 0.04575 .

Note:
The full form of pH is the potential of hydrogen. It ranges from 0140 - 14 . When a solution is acidic, its pH will be less than 77 , and when a solution is basic or alkaline, its pH will be greater than 77 . pH 77 is considered neutral. Pure water has a pH of 77 .