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Question

Question: What is the perpendicular distance of point \[\left( {4,3} \right)\] from x- axes....

What is the perpendicular distance of point (4,3)\left( {4,3} \right) from x- axes.

Explanation

Solution

First we need to recognize or identify the x and y coordinates from a given point. The x-coordinate of the given point is the perpendicular distance of the given point from the y-axis. The y-coordinate of the given point is the perpendicular distance of the given point from the x-axis.

Complete step by step answer:
Let p(x,y)p\left( {x,y} \right) be any point, since the perpendicular distance from y-axis to a point p(x,y)p\left( {x,y} \right) is x-coordinate value and also distance is always positive quantity, Hence, x\left| x \right| is the distance.
Similarly, the perpendicular distance from x-axis to a pointp(x,y)p\left( {x,y} \right) is y-coordinate
Value. Hence, y\left| y \right| is the distance.
In a given point (4,3)\left( {4,3} \right), x-coordinate is 44 and y-coordinate is 33.
Also, the absolute values of x and y coordinates are 44and 33 respectively.
The point (4,3)\left( {4,3} \right) is located in the coordinate plane as shown in the graph below.

clearly, the perpendicular distance from y-axis to a point(4,3)\left( {4,3} \right) is 44 and the perpendicular distance from x-axis to a point(4,3)\left( {4,3} \right) is 33.
Hence the perpendicular distance of point (4,3)\left( {4,3} \right) from x-axes is 33units.

Note:
Note that the lines which are perpendicular to the x-axis are all parallel to the y-axis and they are also known as vertical lines. The lines which are perpendicular to the y-axis are all parallel to the x-axis and they are also known as horizontal lines.
The abscissa of any point (x,y)\left( {x,y} \right) is x-coordinate and the ordinate of any point (x,y)\left( {x,y} \right) is y-coordinate. We use “abscissa” and “ordinate” terms in the solution.