Question
Question: What is the period of \(y = 3\cos 5x\) ?...
What is the period of y=3cos5x ?
Solution
Here we are going to find the period of trigonometric function using the definition of periodic function.
Definition used:
A function is said to be periodic if there exists a positive real number T such that f(x+T)=f(x) for all x∈D where D is the domain of the functionf(x) .
Now for trigonometric function, graphs of trigonometric function clearly show that periods of cosx is 2π . Here we shall mathematically determine periods of few of these trigonometric functions using definition of period.
Complete step-by-step solution:
For cosx to be periodic function,
cos(x+T)=cosx
⇒x+T=2nπ±x , n∈Z
Therefore x+T=2nπ+x or x+T=2nπ−x
First set of value is independent of x hence,
T=2nπ,n∈Z
The least positive value of T that is the period of the function is T=2π .
Now we have to find the periodic function y=3cos5x . We know that the period of the function cosx is 2π.
If we have a function f(x)=cos(ax) where a>0 is the coefficient of the x term, then the period of the functions is T=a2π .
Here we have the periodic function is f(x)=3cos5x The formula for the period of the function is T=a2π.
From given function, a=5
Hence the period of the function T=52π
Note: The smallest positive α∈R for a periodic function f is defined as the fundamental period of f.
Ex:
The function f=sinx is periodic function with set of periods \left\\{ {2n\pi :n \in \mathbb{Z}} \right\\} fundamental period of f=sinx is 2π
Periodicity is the domain based property.
A periodic function may or may not have a fundamental period.
Ex:
f:R→R
f(x)=c,∀x∈R,c∈R
Then for any α∈Rf(x+α)=f(x)=c,∀x∈R
Set of periods is R
But the fundamental period does not exist.
Sum or difference of periodic function may not be periodic. Sum of two non periodic functions may be a periodic function.