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Question

Mathematics Question on Relations and functions

What is the period of the function sin 4x + tan 2x?

A

2π2 \pi

B

π\pi

C

π2\frac{\pi}{2}

D

3π2\frac{3 \pi}{2}

Answer

π2\frac{\pi}{2}

Explanation

Solution

Period of sin x is 2π2 \pi so, period of sin4x=2π4=π2\sin \, 4x = \frac{2 \pi}{4} = \frac{\pi}{2} and period of tan x is π\pi, so period of tan2x=π2\tan \, 2x = \frac{\pi}{2} So, period of (sin4x+tan2x)(\sin \, 4x + \tan \, 2x) = LCM of π2,π2=π2\frac{\pi}{2} , \frac{\pi}{2} = \frac{\pi}{2}