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Question

Physics Question on Wave optics

What is the path difference for destructive interference?

A

nλn\lambda

B

(n+1)λ2\frac{\left(n+1\right)\lambda}{2}

C

n(λ+1)n\left(\lambda+1\right)

D

(2n+1)λ2\frac{\left(2n+1\right)\lambda}{2}

Answer

(2n+1)λ2\frac{\left(2n+1\right)\lambda}{2}

Explanation

Solution

If the waves interfere destructively, then path difference is given by λ2,3λ2,5λ2\frac{\lambda}{2}, \frac{3\lambda}{2}, \frac{5\lambda}{2} etc. Therefore path difference of a destructive interference is (2n+1)λ2\frac{\left(2n+1\right)\lambda}{2} (where n=1,2,3,...)n = 1, 2, 3, ...) etc.