Question

What is the oxidation state of P in $Ba(H_{2}PO_{2})_{2}$?

• A. +3
• B. +2
• C. +1
• D. -1

Answer 1

Answer: (C)

+1

Answer 2

: $Ba\left( H_{2}PO_{2} \right)_{2} \rightarrow + 2 + 4 + 2x + ( - 8) = 0,x = + 1$