Question

What is the oxidation state of $P$ in $Ba(H_2PO_2)_2$?

• A. $+1$
• B. $+2$
• C. $+3$
• D. $-1$

Answer 1

Answer: (A)

$+1$

Answer 2

Let oxidation state of $P$ is $x$, then $2(+1)+2[2(+1)+x+2(-2)]=0$ $2+2(2+x-4)=0$ $2+2x-4=0$ $2x=2$ $x=+1$