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Question

Chemistry Question on Redox reactions

What is the oxidation number of vanadium in Rb4Na[HV10O28]?R b_{4} N a\left[H V_{10} O_{28}\right] ?

A

8

B

5

C

3

D

1

Answer

5

Explanation

Solution

Rb4Na[HV10O28]R b_{4} N a\left[H V_{10} O_{28}\right]
Let oxidation number of VV is xx.
4×1+1+[+1+10x+28(2)]=0\therefore 4 \times 1+1+[+1+10 x+28(-2)]=0
or 4+1+1+10x56=04+1+1+10 x-56=0
or x=+5x=+5