Question

What is the oxidation number of iron in the compound$\lbrack Fe(H_{2}O)_{5}(NO)\rbrack SO_{4}$.

• A. $+ 2$
• B. $+ 3$
• C. $\pm 1$
• D. $\pm 4$

Answer 1

Answer: (A)

$+ 2$

Answer 2

Applying the oxidation number rule in

$\lbrack Fe(H_{2}O)_{5}(NO)\rbrack SO_{4}$ ($\because H_{2}O$ and NO are neutral)

$\lbrack x + (0) \times 5 + 0\rbrack + ( - 2) = 0$

$x + 0 + 0 - 2 = 0$ ⇒ $x = + 2$

Hence, oxidation number of Fe is +2.