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Question: What is the ordered pair that satisfies the equation \[3x + 4y = 24\]?...

What is the ordered pair that satisfies the equation 3x+4y=243x + 4y = 24?

Explanation

Solution

We know that a first degree equation in x and y, ax+by+c=0ax + by + c = 0 always represents a straight line. This form is known as the general form of straight line.
Formula used: From the general form of straight line, ax+by+c=0ax + by + c = 0, we know that

Slope of this line =ab=coeff.of(x)coeff.of(y) = - \dfrac{a}{b} = - \dfrac{{coeff.of(x)}}{{coeff.of(y)}}
Intercept by this line on x-axis=ca = - \dfrac{c}{a}
Intercept by this line on y-axis=cb = - \dfrac{c}{b}
Given: Equation 3x+4y=243x + 4y = 24
To find: Ordered pair that satisfy the given equation, 3x+4y=243x + 4y = 24

Complete step-by-step solution:
Step 1: Conversion of given equation into its general form of equation
We know that the general form of straight line is given by the equation,
ax+by+c=0ax + by + c = 0
Now, rearranging the terms of the given equation 3x+4y=243x + 4y = 24,
Taking 2424on the left hand side of the equation, we get
\Rightarrow $$$$3x + 4y = 24
\Rightarrow $$$$3x + 4y - 24 = 0 (Given equation is now converted into general form of straight line)
Step 2: comparing equations 3x+4y=243x + 4y = 24& ax+by+c=0ax + by + c = 0 both, we get
\Rightarrow $$$$ax + by + c = 0
\Rightarrow $$$$3x + 4y = 24
\Leftrightarrow $$$$a = 3,b = 4\& c = - 24
Step 3: Finding the ordered pair that satisfy the given equation,
Now, from general form of straight line i.e. ax+by+c=0ax + by + c = 0, we know that

  1. Intercept by this line on x-axis =ca = - \dfrac{c}{a}
    Substituting the values of a & c we get,
    Intercept by this line on x-axis =(24)3=8 = - \dfrac{{( - 24)}}{3} = 8& since this intercept is only on x-axis therefore, y=0y = 0
    So, (8,0)(8,0)is a point that satisfy the equation 3x+4y=243x + 4y = 24
  2. Intercept by this line on y-axis=cb = - \dfrac{c}{b}
    Substituting the values of b & c we get,
    Intercept by this line on y-axis =(24)4=6 = - \dfrac{{( - 24)}}{4} = 6& since this intercept is only on y-axis therefore, x=0x = 0
    So, (0,6)(0,6) is a point that satisfy the equation 3x+4y=243x + 4y = 24
    Hence, (8,0)(8,0) &(0,6)(0,6)are the ordered pairs that satisfies the equation 3x+4y=243x + 4y = 24.

Note: Here we need to remember few important properties of straight line.

Equation of line parallel to line ax+by+c=0ax + by + c = 0 is, ax+by+λ=0ax + by + \lambda = 0
Equation of line perpendicular to line ax+by+c=0ax + by + c = 0 is, bxay+k=0bx - ay + k = 0
Here λ\lambda , kk are parameters and their values are obtained with the help of additional information given in the problem.