Question

What is the number of moles of beryllium atoms in $36$ g of Be?

Answer 1

We know that the number of moles is the measure of the atoms of any compound. One mole of any compound contains an Avogadro number of atoms or particles that is $6.022\times {{10}^{23}}$ atoms. These atoms are considered as one mole, which is also the molar mass of any atom, which means the molar mass of any atom.

Complete answer:
The mole is the term that is used to denote a quantity of Avogadro number of particles. It is the number of atoms that are $6.022\times {{10}^{23}}$ , these particles constitute one mole of any substance. The atomic mass of any substance is equal to these numbers of particles that are considered as one mole. As the molar mass of the compounds increases, the number of molecules present in that compound decreases. Here the maximum number of molecules are present $36$ grams.
The mole is characterized as the mass of the substance which comprises the equivalent number of essential units. Example: The number of molecules in twelve grams is equivalent to twelve carbons. The essential units can be particles, molecules or equation unit’s dependent on the substance. The quantity of chemical substance in a reaction is given mole fraction. One mole of any substance is equivalent to Avogadro number. It very well may be utilized to gauge the items acquired from the compound reaction. The unit is meant by mole.
The atomic mass of beryllium $=9.012gmo{{l}^{-1}}$
Thus, Avogadro's number of beryllium atoms has a mass just over $9$ g, since ${{N}_{A}}=$Avogadro's number $=6.022\times {{10}^{23}}.$
Thus, number of beryllium atoms $=\dfrac{36g}{9.012gmo{{l}^{-1}}}\times 6.022\times {{10}^{23}}=2.4\times {{10}^{24}}.$

Note:
Remember that the mole is basically a number of particles. Usually, the particles checked are chemically indistinguishable elements, and exclusively particular. If a solution contains a specific number of broken up atoms that are pretty much autonomous of one another.