Solveeit Logo

Question

Question: What is the number of \(H\) atoms in \(0.183mole\,{C_6}{H_{14}}O\) ?...

What is the number of HH atoms in 0.183moleC6H14O0.183mole\,{C_6}{H_{14}}O ?

Explanation

Solution

In order to this question, to know the number of HH atoms in 0.183moleC6H14O0.183mole\,{C_6}{H_{14}}O , we will first find the number of HH atoms in one mole of given compound. And then go for the final step.

Complete answer:
One mole of C6H14O{C_6}{H_{14}}O contains 14moles14moles of hydrogen atoms. This can be written as:
14molHatoms1molC6H14O\dfrac{{14mol\,H\,atoms}}{{1mol\,{C_6}{H_{14}}O}} .
To determine how many moles of hydrogen are contained in 0.183moleC6H14O0.183mole\,{C_6}{H_{14}}O , multiply 0.183moleC6H14O0.183mole\,{C_6}{H_{14}}O times 14 moles of H atoms per 1 mole of  C6H14O14{\text{ }}moles{\text{ }}of{\text{ }}H{\text{ }}atoms{\text{ }}per{\text{ }}1{\text{ }}mole{\text{ }}of\;{C_6}{H_{14}}O . Then multiply times 6.022×1023atoms H6.022 \times {10^{23}}atoms{\text{ }}H .
0.183molC6H14O×14molHatoms1molC6H14O×6.022×1023Hatoms1molHatoms =1.54×1024Hatoms \begin{gathered} \therefore 0.183mol\,{C_6}{H_{14}}O \times \dfrac{{14mol\,H\,atoms}}{{1mol\,{C_6}{H_{14}}O}} \times \dfrac{{6.022 \times {{10}^{23}}\,H\,atoms}}{{1mol\,H\,atoms}} \\\ = 1.54 \times {10^{24}}\,H\,atoms \\\ \end{gathered}
There are 1.54×1024Hatoms1.54 \times {10^{24}}\,H\,atoms in 0.183moleC6H14O0.183mole\,{C_6}{H_{14}}O .

Note:
Hydrogen’s tendency to rise quickly, a hydrogen leak indoors would briefly collect on the ceiling and eventually move toward the corners. For that and other reasons, industry often uses hydrogen sensors to help detect hydrogen leaks and has maintained a high safety record using them for decades.