Question

What is the normality of $2 M$ ${{H}_{2}}S{{O}_{4}}$?

Answer 1

An attempt to this question can be made by determining the meaning of normality. Based on that you can devise the formula to calculate normality of a solution. Normality is often considered as a term to denote concentration. The formula to calculate normality is given below:
$N = M \times n.f$
Where,
N stands for normality of the solution
M stands for the molarity of the solution
n.f stands for n - factor of the solution

Complete step by step answer:
We will determine the meaning of the terms, molarity, n-factor and normality.
Molar concentration also known as molarity is a measure of the concentration of a chemical species or substance, in particular of a solute in a solution. It is measured in terms of amount of substance per unit volume of solution.
N-factor is defined as the number of ${{H}^{+}}$ ions replaced by 1 mole of base in the reaction.
Normality as per standard definition is described as the number of gram or mole equivalents of solute present in one litre of a solution.
It is given to us that the molarity of ${{H}_{2}}S{{O}_{4}}$ solution is 2.
The n-factor of ${{H}_{2}}S{{O}_{4}}$ is 2.
Substituting the values in the formula, we get
$N = M \times n.f$
$N = 2 \times 2$
$N = 4$
From the above statements we can conclude that the normality of $2 M$ ${{H}_{2}}S{{O}_{4}}$ is $4$.

Note: Normality can alternatively be defined as the actual number of moles of reactive units in a given compound.