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Question

Question: What is the name of \(PbHP{{O}_{4}}\) ?...

What is the name of PbHPO4PbHP{{O}_{4}} ?

Explanation

Solution

While writing the name of an ionic compound we are supposed to write the cation name first and later anion name should be written. Identification of the cationic part and anionic part is crucial while writing the name for an ionic compound

Complete answer:
- In the question it is asked to write the name of PbHPO4PbHP{{O}_{4}} .
- We have to identify if the given compound is ionic or not.
- We know that the given compound PbHPO4PbHP{{O}_{4}} is ionic in nature.
- The common name of the salts can be written as Metal (charge) anion.
- Now in the given chemical the metal is lead (Pb) in the form of Pb+2P{{b}^{+2}} and the anion is HPO42HPO_{4}^{-2} .
- Means the oxidation state of lead is +2.
- After dissolving in water the chemical PbHPO4PbHP{{O}_{4}} is going to split in the following way.
PbHPO4Pb2++HPO42PbHP{{O}_{4}}\to P{{b}^{2+}}+HPO_{4}^{-2}
- From the above chemical equation we can say that the oxidation number of the lead in PbHPO4PbHP{{O}_{4}} is +2.
- Therefore the chemical name is lead (II) hydrogen phosphate.
- The chemical name of Pb2(HPO4)4P{{b}_{2}}{{(HP{{O}_{4}})}_{4}} is different form the chemical name of the PbHPO4PbHP{{O}_{4}} .
- The chemical name of Pb2(HPO4)4P{{b}_{2}}{{(HP{{O}_{4}})}_{4}} is lead (IV) hydrogen phosphate.

Note:
The oxidation state of the cation part is supposed to be represented in roman numerals in brackets after the name of the cation in the chemical name of the compound. In the given chemical roman number (II) gives the information about the oxidation state of the Lead.