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Question

Question: What is the \(n^{th}\) term of the arithmetic sequence 1,9,17,25?...

What is the nthn^{th} term of the arithmetic sequence 1,9,17,25?

Explanation

Solution

The equation to find the nthn^{th} term or a general term of an arithmetic sequence is given as tn=a+(n1)d{{t}_{n}}=a+\left( n-1 \right)d , where tn{{t}_{n}} is the nthn^{th} term of the sequence, a is the first term of the sequence, n is the number of terms and d is the common difference of the sequence. We can use this equation to find the nthn^{th} term of the given arithmetic sequence.

Complete step by step answer:
An arithmetic sequence is defined as one whose successive terms have a common difference. The given sequence in the question is 1,9,17,25. We can use the formula for the nthn^{th} term of an arithmetic sequence to solve this question. It is given as tn=a+(n1)d{{t}_{n}}=a+\left( n-1 \right)d.
From the sequence given, we can clearly see that the first term a is equal to 1. The common difference can be found as the difference of any two successive terms. Taking the first two terms, we get the common difference as,
d=91 d=8 \begin{aligned} & \,\,\,\,\,\,d=9-1 \\\ & \Rightarrow d=8 \\\ \end{aligned}
Finally, substituting these values in the equation for nthn^{th} term of an arithmetic sequence, we get,
tn=a+(n1)d tn=1+(n1)8 tn=1+8n8 tn=8n7 \begin{aligned} & \,\,\,\,\,\,{{t}_{n}}=a+\left( n-1 \right)d \\\ & \,\,\,\,\,\,{{t}_{n}}=1+\left( n-1 \right)8 \\\ & \Rightarrow {{t}_{n}}=1+8n-8 \\\ & \Rightarrow {{t}_{n}}=8n-7 \\\ \end{aligned}

Therefore, the nthn^{th} term of the given sequence is given by tn=8n7{{t}_{n}}=8n-7.

Note: After finding the nthn^{th} term of the sequence, we can cross check or verify if the expression is correct by substituting n starting from 1 and comparing them with the given sequence. For example, let us substitute n as 1 in the expression we have found, we get,
t1=8(1)7 t1=1 \begin{aligned} & {{t}_{1}}=8\left( 1 \right)-7 \\\ & {{t}_{1}}=1 \\\ \end{aligned}
Hence this matches with the sequence. For n=2n=2 , we get,
t2=8(2)7 t2=9 \begin{aligned} & {{t}_{2}}=8\left( 2 \right)-7 \\\ & {{t}_{2}}=9 \\\ \end{aligned}
Even this value agrees with the given sequence. For n=3n=3 , we get,
t3=8(3)7 t3=17 \begin{aligned} & {{t}_{3}}=8\left( 3 \right)-7 \\\ & {{t}_{3}}=17 \\\ \end{aligned}
Even this value agrees with the given sequence. Finally, for n=4n=4 , we get,
t4=8(4)7 t4=25 \begin{aligned} & {{t}_{4}}=8\left( 4 \right)-7 \\\ & {{t}_{4}}=25 \\\ \end{aligned}
Therefore, all the values match with the given sequence and the expression for the nthn^{th} term of the sequence is verified to be correct.