Question

What is the molecular formula of Strontium Chloride?
A) $SnC{l_2}$
B) $SrC{l_2}$
C) $PbC{l_2}$
D) None of the above

Answer 1

The strontium is a divalent atom having an ionic symbol $Sr$2+. We need to know that $Sr$ has $+ 2$ valency whereas chloride has $- 1$ valency therefore, the formula of strontium chloride turns out to be $SrC{l_2}$.

Complete step by step answer:
We need to know that the strontium chloride is an inorganic salt containing strontium and chlorine atoms. The salt so formed has no charge on it making it a neutral salt. We also need to know that the $Sr$ is an alkaline earth metal having atomic number $38$ and we also know that it has its properties intermediate between $Ba$ and $Ca$.
Electronic configuration of $Sr$: $\left[ {Kr} \right]5{s^2}$
Now we discuss about the preparation of strontium chloride as,
$SrC{l_2}$can be prepared by using strontium hydroxide and hydrochloric acid:
$Sr{\left( {OH} \right)_2} + 2HCl \to SrC{l_2} + 2{H_2}$ We can be draw the structure of $SrC{l_2}$ can be represented as:

Let's look at the given options:
Option A) this is an incorrect option as $SnC{l_2}$ this is tin chloride.
$Sn$ is an atomic symbol of Tin.
Option B) This is a correct option as $SrC{l_2}$ is a correct molecular formula for strontium chloride as explained above.
Option C) this is an incorrect option as $PbC{l_2}$ this is lead chloride.
$Pb$ is an atomic symbol of lead.
Option D) this is an incorrect option as we got a correct option as option A.

Hence, the correct answer is, ‘Option A’.

Note: The strontium chloride has a molecular weight of $158.53g/mol$ . We have to know that it is white crystalline powder and an odorless salt. The solubility of $SrC{l_2}$is in water and little in alcohol.