Question

What is the molarity of a solution prepared by dissolving $1.56g$ of gaseous $HCl$ Whose molar mass is $36.5gmo{l^{ - 1}}$ into enough water to make $26.8ml$ of solution?

Answer 1

Molarity is one of the units used to express the amount of concentration. It can be determined by taking the mass of the sample, molar mass of solute, and volume of solution in liters or milliliters. By substituting all the above values, molarity will be obtained.
Formula used:
$M = \dfrac{w}{m} \times \dfrac{{1000}}{V}$
$M$ is molarity
$w$ is weight of gaseous hydrochloric acid
$m$ is molarity of gaseous hydrochloric acid
$V$ is the volume of solution in millilitres

Complete answer:
Molarity is also known as molar concentration, that can be defined as the amount of solute that dissolved in the volume of solution in litres.
Given that a gaseous hydrochloric acid is taken whose mass is given by $1.56g$ and the molar mass of gaseous hydrochloric acid is given as $36.5gmo{l^{ - 1}}$
The volume of solution in millilitres is given as $26.8ml$
Substitute all the values in the above formula, to determine the molarity
$M = \dfrac{{1.56}}{{36.5}} \times \dfrac{{1000}}{{26.8}}$
By simplifying all the above values, the molarity of gaseous hydrochloric acid will be $M = 1.59$
Thus, molarity of of a solution prepared by dissolving $1.56g$ of gaseous $HCl$ Whose molar mass is $36.5gmo{l^{ - 1}}$ into enough water to make $26.8ml$ of solution is $1.59M$

Note:
While calculating the molarity, the exact molar mass should be taken from the molar mass of all the atoms based on the periodic table. The volume of solution must be clearly identified whether it is given in litres or millilitres. If it is given in millilitres, then the volume should be multiplied with a factor of $1000$ as one litre is equal to $1000$ millilitres.