Question

What is the molarity of a $HCl$ solution that contains $14.2g$ of $HCl$ in $182mL$ of solution?

Answer 1

The molar fixation (likewise called molarity, sum focus or substance focus) is a proportion of the grouping of synthetic animal varieties specifically of a solute in an answer, as far as measure of substance per unit volume of arrangement. In science, the most usually utilized unit for molarity is the quantity of moles per liter, having the unit image $mol/L$ or $mol.d{m^{ - 3}}$ in $SI$ unit. An answer with a centralization of $1mol/L$ is supposed to be one molar, normally assigned as $1M$ .

Complete step by step answer:
We have to know molarity can change with temperature and volume. As the temperature builds, molarity diminishes. Additionally, when the volume of an answer expands, the molarity diminishes. The molarity of an answer likewise relies upon the solvency of the solute and if any extra substances are added to the arrangement, molarity has an immediate relationship with the measure of solute in an answer. This implies that as the measure of solute expansions in the arrangement, so will the molarity.
We have to know the formula of molarity, that has to be given below,
$M = \dfrac{n}{v}$
Where,
$M$ = Molarity
$N$ = number of moles
$V$ = volume in liter.
Then, first, we have to convert $14.2g$ of $HCl$ in to moles,
The molar mass of $HCl$ is $36.46g/mol$,
Therefore,
$= {\text{ }}\dfrac{{14.2g}}{{36.46g/mol}}{\text{ }} = {\text{ 0}}{\text{.39 moles}}$
Then, converting $182mL$ into liter,
Therefore,
$182mL{\text{ = 0}}{\text{.182L}}$
Applying all the values in the molarity equation,
$M{\text{ = }}\dfrac{n}{V}{\text{ = }}\dfrac{{0.39mol}}{{0.182l}}{\text{ = 2}}{\text{.14 mol/L}}$
Hence,
The molarity of $HCl$ is $2.14mol/L$ .

Note: We have to know the molarity, molality, and normality are large units of fixation in science. Molarity ( $M$ ) is characterized as the quantity of moles of solute per liter of arrangement. Molality ( $m$ ) is characterized as the quantity of moles of solute per kilogram of dissolvable. Normality ( $N$ ) is characterized as the quantity of counterparts per liter of arrangement.