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Question

Physics Question on Gravitation

What is the minimum energy required to launch a satellite of mass mm from the surface of a planet of mass MM and radius RR in a circular orbit at an altitude of 2R2\,R ?

A

5GmM6R \frac{ 5GmM}{6 R}

B

2GmM3R \frac{ 2GmM}{3 R}

C

GmM2R \frac{ GmM}{2 R}

D

GmM3R \frac{ GmM}{3 R}

Answer

5GmM6R \frac{ 5GmM}{6 R}

Explanation

Solution

E = Energy of satellite - energy of mass on the surface of planet
=GMm2r(GMmR)= -\frac{GMm}{2r} -\bigg( - \frac{GMm}{ R} \bigg)
Here, r = R + 2R = 2>R
Substituting in about equation we get. E=5GMm6RE = \frac{ 5GMm}{ 6R}