Question
Question: What is the minimum concentration of \(S{O_4}^{2 - }\) required to precipitate \(BaS{O_4}\) in a sol...
What is the minimum concentration of SO42− required to precipitate BaSO4 in a solution containing 1×10−4 mole of Ba+2 and Ksp of BaSO4=4×10−10 ?
Solution
Write down the equation for the reaction of precipitation of BaSO4 and then from this formula, calculate the formula for Ksp with the concentrations of Ba+2 and SO42− . The concentration of Ba+2 is already given so the concentration of SO42− can be calculated accordingly.
Complete answer:
We can write the precipitation reaction of BaSO4 as follows
BaSO4→Ba2++SO42−
Now we calculate the equation for Ksp from this equation
Ksp=[Ba2+][SO42−]
The concentration of Ba2+ and the value of Ksp is already given to us. By substituting these values in the above equation, we get
4×10−10=1×10−4×[SO42−]
We solve this to get the value of concentration of SO42−
[SO42−]=1×10−44×10−10
By solving, [SO42−]=4×10−6
Therefore, the concentration of SO42− required to precipitate BaSO4 is 4×10−6
Additional information: When two solutions containing certain soluble salts are combined together, sometimes an insoluble salt is formed which is called a precipitate. This process of formation of a precipitate is known as Precipitation reaction. These reactions are mainly double displacement reactions and they help us in determining the presence of different salts in a solution. These reactions can be used to determine the presence of minerals as they are water-insoluble.
Note: One must always balance a reaction before deriving the formula for Ksp . This holds significance since the number of molecules of a substance becomes the power of the concentration in the derived formula. Since the above reaction contains only one molecule of products and reactants, the power on the concentration remains one.