Question
Question: What is the mean of first n odd natural numbers? \( {\text{A}}{\text{. n}} \\\ {\text{B}}{...
What is the mean of first n odd natural numbers?
A. n B. 2n + 1 C. 2n(n + 1) D. n + 1
Solution
Hint – To find the mean, we observe the numbers are in arithmetic progression. Then we find the nth term of the progression and then we find the sum of first n odd natural numbers by using the first and the nth odd number.
Complete step-by-step answer:
We know the first n odd terms are in arithmetic progression with common difference (d) = 2, i.e. the difference between any two consecutive numbers is two.
We know, the first odd natural number (a) = 1
We know the nth odd natural number can be given as (an) = a + (n-1) d
Where a is the first term, n is the number of terms of the progression and d is the common difference.
= 1 + (n – 1) x 2
= 1 + 2n -1
= 2n -1
Where n belongs to the set of natural numbers = (1, 2, 3…)
We know, sum of first n terms in AP can be given as = 2n(a + an)
Therefore, sum of first n odd natural numbers
= 2n(1 + 2n - 1)
= 2n(2n)
= n2
We know Mean can be given as = Total number of termsSum of all terms
Mean of first n odd natural numbers = Total number of first n odd natural numbersSum of first n odd natural numbers
Mean of first n odd natural numbers = nn2
⟹Mean of first n odd natural numbers = n
Hence, Mean of first n odd natural numbers is n. Option A is the correct answer.
Note – The key in solving such types of problems is to identify that the numbers are in arithmetic progression. Then the next crucial steps are finding the nth term and sum of terms using the formulas of AP. The sum of first n odd natural numbers divided by the first n odd natural numbers gives the mean.