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Question: What is the mean of first n odd natural numbers? \( {\text{A}}{\text{. n}} \\\ {\text{B}}{...

What is the mean of first n odd natural numbers?
A. n B. n + 12 C. n(n + 1)2 D. n + 1  {\text{A}}{\text{. n}} \\\ {\text{B}}{\text{. }}\dfrac{{{\text{n + 1}}}}{2} \\\ {\text{C}}{\text{. }}\dfrac{{{\text{n}}\left( {{\text{n + 1}}} \right)}}{2} \\\ {\text{D}}{\text{. n + 1}} \\\

Explanation

Solution

Hint – To find the mean, we observe the numbers are in arithmetic progression. Then we find the nth{{\text{n}}^{{\text{th}}}} term of the progression and then we find the sum of first n odd natural numbers by using the first and the nth{{\text{n}}^{{\text{th}}}} odd number.

Complete step-by-step answer:

We know the first n odd terms are in arithmetic progression with common difference (d) = 2, i.e. the difference between any two consecutive numbers is two.

We know, the first odd natural number (a) = 1
We know the nth{{\text{n}}^{{\text{th}}}} odd natural number can be given as (an{{\text{a}}_{\text{n}}}) = a + (n-1) d
Where a is the first term, n is the number of terms of the progression and d is the common difference.
= 1 + (n – 1) x 2
= 1 + 2n -1
= 2n -1
Where n belongs to the set of natural numbers = (1, 2, 3…)

We know, sum of first n terms in AP can be given as = n2(a + an)\dfrac{{\text{n}}}{2}\left( {{\text{a + }}{{\text{a}}_{\text{n}}}} \right)
Therefore, sum of first n odd natural numbers
= n2(1 + 2n - 1)\dfrac{{\text{n}}}{2}\left( {1{\text{ + 2n - 1}}} \right)
= n2(2n)\dfrac{{\text{n}}}{2}\left( {{\text{2n}}} \right)
= n2{{\text{n}}^2}

We know Mean can be given as = Sum of all termsTotal number of terms\dfrac{{{\text{Sum of all terms}}}}{{{\text{Total number of terms}}}}

Mean of first n odd natural numbers = Sum of first n odd natural numbersTotal number of first n odd natural numbers\dfrac{{{\text{Sum of first n odd natural numbers}}}}{{{\text{Total number of first n odd natural numbers}}}}

Mean of first n odd natural numbers = n2n\dfrac{{{{\text{n}}^2}}}{{\text{n}}}
⟹Mean of first n odd natural numbers = n

Hence, Mean of first n odd natural numbers is n. Option A is the correct answer.

Note – The key in solving such types of problems is to identify that the numbers are in arithmetic progression. Then the next crucial steps are finding the nth{{\text{n}}^{{\text{th}}}} term and sum of terms using the formulas of AP. The sum of first n odd natural numbers divided by the first n odd natural numbers gives the mean.