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Question

Question: What is the maximum number of emission lines when the excited electron of a hydrogen atom in n = 6 d...

What is the maximum number of emission lines when the excited electron of a hydrogen atom in n = 6 drops to ground state?

A

6

B

15

C

30

D

10

Answer

15

Explanation

Solution

: Maximum number of emission lines, =n(n1)2= \frac{n(n - 1)}{2}

=6(61)2=302=15= \frac{6(6 - 1)}{2} = \frac{30}{2} = 15 lines