Question
Question: What is the mass percentage of carbon tetrachloride if \(22g\) of benzene is dissolved in \(122g\) o...
What is the mass percentage of carbon tetrachloride if 22g of benzene is dissolved in 122g of carbon tetrachloride?
A: 84.72%
B: 15.28%
C: 50%
D: 44%
Solution
Like molarity and molality mass percentage is also one of the ways to represent the concentration of the solution. It is calculated by dividing the mass of the component with the total mass of the mixture, multiplied by 100.
Formula used: mass percent=Mm×100
Where m is mass of the substance and M is mass of a mixture
Complete step by step answer:
We know the mass percent of a substance is calculated as the mass of that substance divided by the total mass of the mixture. In this question, we have given the mass of carbon tetrachloride and benzene. We have to calculate the mass percentage of carbon tetrachloride in the mixture of benzene and carbon tetrachloride. We need to write a mass of substance and mass of the mixture.
Mass of substance (carbon tetrachloride) m=122g (given)
Mass of benzene =22g (given)
Mass of mixture= mass of benzene+mass of carbon tetrachloride
Mass of mixture(M)=22+122=144g
Using above formula, mass percent=Mm×100
We get,
Mass percent=144122×100
Mass percent=84.722%
Mass percent of carbon tetrachloride is 84.72%.
So, correct answer is option A that is 84.72%.
Additional information:
Normality is also a way to define concentration. It is defined as the number of gram equivalents present per 1000mL of solution. Equivalent mass is calculated by dividing the molecular mass of substance with valency.
Note:
Molarity and molality both are two different terms. In molality mass of the solvent is used and in molarity volume of solution is used. Molarity is defined as the number of moles present per 1000mL of solution and molality is defined as the number of moles present per Kg of solvent.