Question

What is the mass of one atom of copper in grams?

Answer 1

The amount of substance or element can be expressed in different forms like moles, number of atoms, grams.
To convert the number of atoms of a particular element, we should need molar mass of that element and Avogadro’s number. The number of atoms of an element of the compound should be multiplied with molar mass and divided by Avogadro’s number.

Complete answer:
The periodic table consists of different elements arranged in vertical columns and horizontal rows.
These different elements are arranged in the increasing order of atomic numbers.
The periodic table consists of a total of $118$ elements.
The vertical columns are called groups and horizontal rows are called periods.
There are $7$ periods and $18$ groups in the periodic table.
Copper is an element belonging to period $4$ and group $11$ .
It is a metal and does not readily participate in chemical reactions.
Copper has anonymous electronic configuration to attain completely filled subshell configuration.
It has an atomic number of $29$ , and has the molar mass of $63.55gm{\left( {mol} \right)^{ - 1}}$
Thus, $\text{1 mole of Cu} = 63.5gm$
The mole is also a quantity used to express the amount of substance.
But, $1mole = 6.023 \times {10^{23}}$ particles.
The above number is called Avogadro’s number.
These particles can be atoms or molecules or groups.
Thus, to convert the substance present in the number of atoms to grams, the Avogadro’s number should also be considered.
Thus, the molar mass of copper, Avogadro’s number, should be multiplied to convert the number of atoms into grams.
$1atomCu \times \dfrac{{1moleCu}}{{6.023 \times {{10}^{23}}atomsCu}} \times \dfrac{{63.5gCu}}{{1molCu}} = 1.05 \times {10^{ - 22}}gCu$
Thus, 1 atom of copper contains $1.05 \times {10^{ - 22}}gm$ .

Note:
The molar mass of copper must be taken accurately. Significant figures must also be taken. Avogadro's number should be taken clearly. It is the number of particles or ions or elements present in one mole.