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Question: What is the mass of 4.30 mole of sodium?...

What is the mass of 4.30 mole of sodium?

Explanation

Solution

Let us first understand what a mole is. One of the SI units of measurement that can be used to determine the amount of a substance is a mole. A mole of any substance has exactly 6.022×10236.022\times {{10}^{23}} particles which can be ions, atoms, electrons, or molecules.

Complete answer:
We know that if one mole of a substance is present, it has exactly the Avogadro number (NA)({{N}_{A}}) of particles.
NA=6.022×1023{{N}_{A}}=6.022\times {{10}^{23}}
Now, the sum of the mass of all the particles in a sample gives the mass of a sample.
So, we can say that the mass of one mole of a compound is equivalent to the mass of all the particles contained in one mole of a substance i.e., 6.022×10236.022\times {{10}^{23}} particles.
The molar mass of a substance is the mass of one mole of a substance. Even though it is usually expressed in g/mol, its SI base unit is kg/mol. Molar mass of a substance is not a molecular property, rather it is a bulk property of the substance.
Now, the molar mass of a substance is calculated by dividing the mass of the sample given and the number of moles of the sample given.
M=mnM=\dfrac{m}{n}
So, the mass of a sample containing a given number of moles can be given by
mm =n×Mn\times M
Where n = number of moles,
m = mass of given sample (in grams), and
M = molar mass of the sample (in g/mol).
Now, it is given to us that the number of moles n = 4.30.
And the molar mass of sodium (Na) is approximately M = 23 u
So, the mass of the sample containing 4.30 moles of sodium will be
m=4.3×23m=4.3\times 23
m = 98.9 g.

Note:
It must be noted that in 2019, the SI base unit of molar mass was redefined. According to the new definition, the molar mass constant is
Mu=0.99999999965×103kg/mol{{M}_{u}}=0.99999999965\times {{10}^{-3}}kg/mol
And not 1×103kg/mol1\times {{10}^{-3}}kg/mol.
But for practical purposes, the molar mass of an element is still considered to be equivalent to the atomic mass of the element since the change is so insignificant.