Question

What is the mass of 19.42 atoms of F?

Answer 1

Hint : In the given question firstly we have to define what exactly is the Fluorine and how can we determine it and give the proper definition and the physical characteristics of it. And we also have to use the concept of mole and Avogadro’s number to determine the answer, which is $6.022 \times {10^{23}}$ .

Complete Step By Step Answer:
The given question statement asks about the Fluorine and the weight of its given value of atoms. We have to provide the basic definition and the other important characteristics for finding value.
Now we know that Fluorine is a chemical element with the symbol F and its atomic number is 9. It is also the lightest halogen and also exists at as a standard condition as a highly toxic, pale yellow diatomic gas. It is also regarded as the most electronegative element and is extremely reactive, as it reacts with all other elements, except for argon, neon, and helium.
Now we know that the mass of 1 mole F = $19g$
So we can say that the mass of $6.022 \times {10^{23}}$ F = $19g$
Now the mass of 1 F atom should be = $\dfrac{{19}}{{6.022 \times {{10}^{23}}}}$
Thus the mass of 19.42 F Atoms :
= 19.42 \times \dfrac{{19}}{{6.022 \times {{10}^{23}}}} \\\ = \dfrac{{19.42 \times 19}}{{6.022 \times {{10}^{23}}}} \\\ = 6.127 \times {10^{ - 22}}g \\\
So we can say that the mass of the 19.42 atoms of F = $6.127 \times {10^{ - 22}}g$ .

Note :
In 1529, Georgius Agricola described fluorite as an additive used to lower the melting point of metals during smelting. He penned the Latin word fluorēs (fluor, flow) for fluorite rocks. The name later evolved into fluorspar (still commonly used) and then fluorite.