Question

What is the mass of $0.0914$ moles of Ammonium sulfate?

Answer 1

Ammonium sulfate contains molecules of ammonium ion and one molecule of sulfate ion. It is an inorganic salt with many uses in industries. The maximum not unusual place to use is as a soil fertilizer. It includes $21\%$ Nitrogen and $24\%$ Sulfur. To solve the given problem, we use the following formula:
$\text{Molar mass} = \dfrac{\text{Mass}}{\text{Number of moles}}$
Molar mass of Ammonium sulfate is 132.14 g/mol.

Complete answer:
The mole is a diploma or the lowest unit for the amount of substance present inside the aspect of the given sample. 1 mole is a huge range; it truly is identical to particles, moreover known as the Avogadro's constant.
A number of moles can be calculated as mass of Ammonium sulfate divided by the molar mass.
For ammonium sulfate, It is given that the number of moles = $0.0914$
Let the mass of Ammonium sulfate be $x$ $g/mol$.
And Molar mass of Ammonium sulfate is approximately $132$ g/mol
Substituting these values in the formula,
$\text{Number of moles} = \dfrac{\text{Mass}}{\text{Molar mass}}$
We get
$0.0914 = \dfrac{x}{{132}}$
Solving for $x$,

$\Rightarrow x = 0.0914 \times 132$

$\Rightarrow x = 12.06g/mol$

Therefore, the mass of $0.0914$ moles of Ammonium sulfate is 12.06 g/mol.

Note:
Double metallic sulfates consist of ammonium cobalt sulfate, ferrous di-ammonium sulfate, ammonium nickel sulfate which might be referred to as Tutton's salts, and ammonium ceric sulfate. An anhydrous double sulfate of ammonium additionally arises withinside the Langbeinites family. The ammonia produced has a stinky odor and is toxic.