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Question: What is the magnitude of the gravitational force exerted by a \[15Kg\] mass on a \[25Kg\] mass separ...

What is the magnitude of the gravitational force exerted by a 15Kg15Kg mass on a 25Kg25Kg mass separated by a distance of 25cm25cm? What is the acceleration produced in each mass?

Explanation

Solution

In order to solve this question, we are going to first see the given information, i.e. the two masses and their distance and then, by using the law of gravitation formula, the acceleration of the two bodies can be calculated by putting the values of masses and that of gravitational constant.

Formula used:
The acceleration of the first body can be calculated by using the formula for the law of Gravitation
a=Gmd2a = \dfrac{{Gm}}{{{d^2}}}

Complete step-by-step answer:
It is given that the mass of the first body is m1=15Kg{m_1} = 15Kgand the mass of the second body is m2=25Kg{m_2} = 25Kg
Now, they are separated by a distance of d=25cmd = 25cm
Now the acceleration of the first body can be calculated by using the formula for the law of Gravitation
a1=Gm1d2{a_1} = \dfrac{{G{m_1}}}{{{d^2}}}
Where G=6.674×1011G = 6.674 \times {10^{ - 11}}
Putting the values in this equation
a1=6.674×1011×15252=2.67×108ms2{a_1} = \dfrac{{6.674 \times {{10}^{ - 11}} \times 15}}{{{{25}^2}}} = 2.67 \times {10^{ - 8}}m{s^{ - 2}}
The acceleration for the second body can be calculated by using the formula
a2=Gm2d2{a_2} = \dfrac{{G{m_2}}}{{{d^2}}}
Putting these values in the equation
a2=6.674×1011×25252=1.6×108ms2{a_2} = \dfrac{{6.674 \times {{10}^{ - 11}} \times 25}}{{{{25}^2}}} = 1.6 \times {10^{ - 8}}m{s^{ - 2}}

Note: It is important to note that the accelerations of the two bodies are due to their masses and their positions as there are the gravitational forces that are acting between these two masses and that force depends on the masses of the bodies, their distance and the gravitational constant. The mass of the second body is more, so the acceleration is also more.