Question

What is the magnitude of magnetic force per unit length on a wire carrying a current of 8 A and making an angle of 30º with the direction of a uniform magnetic field of 0.15 T?

Answer 1

Current in the wire, $I$ = 8 A
Magnitude of the uniform magnetic field, $B = 0.15 T$
Angle between the wire and magnetic field, $θ = 30°$
Magnetic force per unit length on the wire is given as:$F = BISinθ$
$= 0.15 × 8 ×1 × sin30°$
$= 0.6 N m^{–1}$
Hence, the magnetic force per unit length on the wire is $0.6 N m^{–1}.$