Question
Question: What is the magnitude of Gravitational force between the earth and a \(1kg\) object on its surface? ...
What is the magnitude of Gravitational force between the earth and a 1kg object on its surface? (Mass of earth is 6×1024kg and radius of earth is 6.4×106m).
Solution
Hint
To solve this problem, use the universal law of gravitation, using the data given in the question. The formula for the universal law of gravitation gives us the magnitude of the force of attraction (or the gravitational force) between the two objects.
⇒F=r2GMm
Where F,G,M,m,r represent gravitational force, universal gravitation constant, the mass of the body (1), the mass of the body (2), and the distance between the two bodies respectively.
Complete step by step answer
Newton's law of universal gravitation is usually stated as that every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. From the given data in the question.
⇒M=6×1024kg= Mass of earth
⇒m=1kg= Mass of object
⇒G=6.67×10−11kg2Nm2= Universal gravitational constant
⇒r=6.4×106m= Radius of earth
The distance between the object and the earth is taken as the radius of the earth because by definition the distance is taken from the center of the two bodies. Since the object is placed on the surface of the earth, the distance from the center of the earth to the surface is the same as the radius of the earth.
Substituting the above values in the formula for gravitational force,
⇒F=(6.4×106)26.67×10−11×6×1024×1
⇒F=9.77≈9.8N
So, the magnitude of the gravitational force between the earth and a 1kg object is found to be 9.8N.
Additional Information
Newton has not only given the universal law of gravitation but also gave three other laws of motion. These are considered as the most important laws of physics and they are,
(1) Every object moves in a straight line unless acted upon by a force.
(2) The acceleration of an object is directly proportional to the net force exerted and inversely proportional to the object's mass.
(3) For every action, there is an equal and opposite reaction.
Note
Usually, the distance between the earth and any object placed on earth’s surface is taken equal to the radius of the earth because the size of the object is negligible compared to the size of the earth and it is practically impossible to have an object whose size can be compared to the size of the earth. So, even if the radius of the object is provided to us, it is neglected as it is very less than the radius of the earth.