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Question: What is the magnitude of a point charge which produces an electric field of 2 N/coulomb at a distanc...

What is the magnitude of a point charge which produces an electric field of 2 N/coulomb at a distance of 60 cm (1/4πε0=9×109N−m2/C21/4\pi\varepsilon_{0} = 9 \times 10^{9}N - m^{2}/C^{2})

A

8×10−118 \times 10^{- 11}C

B

2×10−122 \times 10^{- 12}C

C

3×10−113 \times 10^{- 11}C

D

6×10−106 \times 10^{- 10}

Answer

8×10−118 \times 10^{- 11}C

Explanation

Solution

E=14πε0.Qr2E = \frac{1}{4\pi\varepsilon_{0}}.\frac{Q}{r^{2}}⇒ 2=9×109×Q(0.6)22 = 9 \times 10^{9} \times \frac{Q}{(0.6)^{2}}⇒ Q = 8 × 10−11C10^{- 11}C