Question

What is the magnetic moment for ${Mn^{2+}}$ ion?

• A. 5.92 B.M.
• B. 2.80 B.M
• C. 8.95 B.M.
• D. 9.55 B.M.

Answer 1

Answer: (A)

5.92 B.M.

Answer 2

${Mn^{2+}} : 3d^5,$ no. of unpaired electrons $(n) = 5$
Magnetic moment $(\mu) = \sqrt{n(n+2)} \, {B.M.}$
$= { \sqrt{5(5+2)} \, B.M. = \sqrt{35}}$
$= {= 5.92 \,B.M.}$