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Question

Question: What is the limit of \[\tan \left( {\dfrac{1}{x}} \right)\] as x approaches infinity?...

What is the limit of tan(1x)\tan \left( {\dfrac{1}{x}} \right) as x approaches infinity?

Explanation

Solution

In the above question we have to find the limit of tan(1x)\tan \left( {\dfrac{1}{x}} \right) when x approaches infinity. Mathematically, we can also write it as limxtan(1x)\mathop {\lim }\limits_{x \to \infty } \tan \left( {\dfrac{1}{x}} \right) . Now, to find the value of limxtan(1x)\mathop {\lim }\limits_{x \to \infty } \tan \left( {\dfrac{1}{x}} \right) , we consider 1x\dfrac{1}{x} . Here, after finding the limit of 1x\dfrac{1}{x} when x tends to infinity, we can find the limit of tan(1x)\tan \left( {\dfrac{1}{x}} \right) when x tends to infinity simply by putting xx \to \infty .

Complete step by step solution:
Given function is tan(1x)\tan \left( {\dfrac{1}{x}} \right)
We have to find the limit of tan(1x)\tan \left( {\dfrac{1}{x}} \right) when x tends to infinity.
Or, we have to find the value of
limxtan(1x)\Rightarrow \mathop {\lim }\limits_{x \to \infty } \tan \left( {\dfrac{1}{x}} \right)
Now consider limx1x\mathop {\lim }\limits_{x \to \infty } \dfrac{1}{x} ,
When xx will approach infinity, then 1x\dfrac{1}{x} will approach zero.
Or we can write it as,
When xx \to \infty , then 1x0\dfrac{1}{x} \to 0 ...(1)
Now, similarly in limxtan(1x)\mathop {\lim }\limits_{x \to \infty } \tan \left( {\dfrac{1}{x}} \right)
When 1x\dfrac{1}{x} will approach zero, then tan(1x)\tan \left( {\dfrac{1}{x}} \right) will also approach zero.
Because tan(0)=0\tan \left( 0 \right) = 0
Therefore, we can also write it as
When 1x0\dfrac{1}{x} \to 0 then tan(1x)0\tan \left( {\dfrac{1}{x}} \right) \to 0
Using ...(1) , we can write it as
When xx \to \infty then tan(1x)0\tan \left( {\dfrac{1}{x}} \right) \to 0
Hence, now we can write the limit of tan(1x)0\tan \left( {\dfrac{1}{x}} \right) \to 0 as
limxtan(1x)=0\Rightarrow \mathop {\lim }\limits_{x \to \infty } \tan \left( {\dfrac{1}{x}} \right) = 0
Therefore, the limit of tan(1x)\tan \left( {\dfrac{1}{x}} \right) as x approaches infinity is 0.

Note:
When y = f(x) is a function of x and if at a point x = a, f(x) takes indeterminate form, then we can consider the values of the function which is very near to a. If these values tend to some definite unique number as x tends to a, then that obtained unique number is called the limit of f(x) at x = a.
Also, if we have a limit where x tends to a real number a then we can replace the limit xax \to a by a new limit as h0h \to 0 after putting x=a+hx = a + h in the given function.
Mathematically,
limxaf(x)=limh0f(a+h)\Rightarrow \mathop {\lim }\limits_{x \to a} f(x) = \mathop {\lim }\limits_{h \to 0} f\left( {a + h} \right)