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Question: What is the IUPAC name of the following compound \( C{H_3} - C{H_2} - C{H_2} - OH \) (A) Propa...

What is the IUPAC name of the following compound
CH3−CH2−CH2−OHC{H_3} - C{H_2} - C{H_2} - OH
(A) Propan-1-ol
(B) Propan-2-ol
(C) Propane-1-ol
(D) Ethane-2-ol

Explanation

Solution

An alcohol is an organic compound with an aliphatic carbon atom bearing the hydroxyl (OH) functional group. We often represent alcohols by the general formula ROH, where R is an alkyl group, because OH is the functional group of all alcohols. Alcohol is found in abundance in nature. The active ingredient in alcoholic beverages is ethyl alcohol (ethanol), but it is only one of a group of organic compounds known as alcohols.

Complete answer:
The number of carbon atoms in this compound is three. Propane is the parent alkane. OH, or alcohol, is the functional group present. The first carbon atom contains OH. Propan-1-ol is the IUPAC name for this compound.
Alcohols are named by adding -ol to the end of the parent alkane name, according to the International Union of Pure and Applied Chemistry (IUPAC). Some basic IUPAC rules for naming alcohols are as follows:
The parent compound is an alkane with the same number of carbon atoms as the longest continuous chain (LCC) of carbon atoms containing the OH group. From the end closest to the OH group, the chain is numbered.
The OH group's position is indicated by a number prefixed to the parent hydrocarbon's name, and the parent alkane's -e ending is replaced by the suffix -ol. (The carbon atom bearing the OH group is designated C1 in cyclic alcohols, but the 1 is not used in the name.) Substituents are named and numbered in the same way that alkanes are.
Suffixes like -diol and -triol are used when more than one OH group appears in the same molecule (polyhydroxy alcohols). The parent alkane's -e ending is preserved in these cases.
Hence, Option (A) is correct.

Note :
The reactions of 1-propanol are typical of a primary alcohol. Thus, it can be converted to alkyl halides; for example, red phosphorus and iodine yield 90 percent 1-iodopropane, while PCl3PC{l_3} with catalytic ZnCl2ZnC{l_2} yields 1-chloropropane. Propyl acetate is produced by reacting propanol with acetic acid in the presence of an H2SO4{H_2}S{O_4} catalyst under Fischer esterification conditions, whereas refluxing propanol overnight with formic acid alone yields propyl formate in a 65 percent yield.