Question

What is the ionic equation of $KOH+HCl\to KCl+{{H}_{2}}O$?

Answer 1

To solve this question we first need to know what is an ionic equation. When in an aqueous solution, the compounds dissociate into their respective ions and dissolve in the solution. The representation of these ions can be represented using an ionic equation.

Complete answer:
Now, the dissociation of a compound depends upon its solubility.
Potassium hydroxide (KOH), when in an aqueous solution, breaks into two ions, a potassium ${{K}^{+}}$ cation, and a hydroxide $O{{H}^{-}}$ anion.
Similarly, hydrochloric acid (HCl), when in an aqueous solution, breaks into two ions, a proton ${{H}^{+}}$ cation, and a chloride $C{{l}^{-}}$ anion.
From the given reaction, we can see that the products formed when 1 molecule of hydrochloric acid (HCl) and 1 molecule of potassium hydroxide (KOH) react are potassium chloride (KCl) and liquid water (${{H}_{2}}O$).
Potassium chloride (KCl), when in an aqueous solution, breaks into two ions, a potassium ${{K}^{+}}$ cation, and a chloride $C{{l}^{-}}$ anion.
Since water is not present in an aqueous medium but produced in the reaction as a liquid, it is not written as its corresponding dissociated ions.
So, the ionic equation will be
${{K}^{+}}(aq)+O{{H}^{-}}(aq)+{{H}^{+}}(aq)+C{{l}^{-}}(aq)\to {{K}^{+}}(aq)+C{{l}^{-}}(aq)+{{H}_{2}}O(l)$

Note:
It should be noted that an equation in which only those ions are represented the actual process of the chemical process which takes place is known as a net ionic equation.
According to the ionic equation, in the reaction between HCl and KOH, the potassium ${{K}^{+}}$ cation and the chloride $C{{l}^{-}}$ anion do not take part in the chemical equation, although they are found in the reaction solution. These are spectator ions. So, the met ionic equation will be
$O{{H}^{-}}(aq)+{{H}^{+}}(aq)\to {{H}_{2}}O(l)$