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Question: What is the ionic equation for \[N{a_2}C{O_3} + Ba{(N{O_3})_2} \to BaC{O_3} + 2NaN{O_3}?\]...

What is the ionic equation for Na2CO3+Ba(NO3)2→BaCO3+2NaNO3?N{a_2}C{O_3} + Ba{(N{O_3})_2} \to BaC{O_3} + 2NaN{O_3}?

Explanation

Solution

Hint : An ionic equation is a chemical equation where the electrolytes in an aqueous solution are written as dissociated ions. To write an ionic equation for any chemical equation we must follow the set of rules.

Complete Step By Step Answer:
-Balance the complete molecular equation. Prior to composing a net ionic equation, you should initially ensure your beginning equation is totally balanced. To adjust a condition, you add coefficients before compounds until there is an equivalent number of molecules for every component on the two sides of the reaction.
-Distinguish the state of matter of each compound in the equation. In many cases, you will be able to distinguish keywords in a problem that will reveal to you the condition of matter for each compound.
-Figure out what species will (separate into cations and anions) in the arrangement. At the point when the species or compound separates, it isolates into its positive (cation) and negative (anion) parts.
-calculate the charge of each separated ion. Recall that metals will be the positive cation, while non-metals will be the negative anion.
-Re-write the equation with the dissolvable ionic compound separated into their individual particles. Anything that will separate or ionize (solid acids) will basically isolate into its two distinct particles.
-Eliminate the observer particles by offsetting indistinguishable particles on each side of the condition.
According to these rule we will write the ionic equation for the following reaction.
Na2CO3+Ba(NO3)2→BaCO3+2NaNO3N{a_2}C{O_3} + Ba{(N{O_3})_2} \to BaC{O_3} + 2NaN{O_3}
The Ionic equation for the above reaction is:
2Na+1+CO3−2+Ba+2+2NO3−1→2Na+1+2NO3−1+BaCO32N{a^{ + 1}} + C{O_3}^{ - 2} + B{a^{ + 2}} + 2N{O_3}^{ - 1} \to 2N{a^{ + 1}} + 2N{O_3}^{ - 1} + BaC{O_3}
Net ionic equation:
2Na+1+CO3−2+Ba+2+2NO3−1→2Na+1+2NO3−1+BaCO3 Ba+2+CO3−2→BaCO3  2N{a^{ + 1}} + C{O_3}^{ - 2} + B{a^{ + 2}} + 2N{O_3}^{ - 1} \to 2N{a^{ + 1}} + 2N{O_3}^{ - 1} + BaC{O_3} \\\ B{a^{ + 2}} + C{O_3}^{ - 2} \to BaC{O_3} \\\

Note :
Net ionic equation should be adjusted by both mass and charge. Adjusting by mass methods ensuring that there are equivalent quantities of every component. Adjusting by charge implies ensuring that the general charge is something similar on the two sides of the condition.